Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

Which function's graph has asymptotes located at the values x= ±nπ?1-Y=csc x2-Y=cos x 3-Y=tan x4-Y=cot x

Sagot :

Given:

1-Y=csc x

2-Y=cos x

3-Y=tan x

4-Y=cot x​

Required:

To find the functions whose graph has asymptotes located at the values x= ±nπ?

Explanation:

To find the vertical asymptotes the denominator of the function should be zero.

In the given functions cosx has no denominator.

[tex]\begin{gathered} cscx=\frac{1}{\sin x} \\ tanx=\frac{sinx}{cosx} \\ cotx=\frac{cosx}{sinx} \end{gathered}[/tex]

The values of sin function at

[tex]x=0,\pm\pi,\pm2\pi,\pm3\pi,........,\pm n\pi[/tex]

is 0.

The value of cos function at

[tex]x=0,\pm\pi,\pm2\pi,\pm3\pi,..........,\pm n\pi[/tex]

is not 0.

Thus we can observe that the sine function is 0 at the values of

[tex]x=\pm n\pi[/tex]

The cscx and the cotx function has denominator sinx.

Thus the functions cscx and cotx graph have asymptotes located at the values x= ±nπ?

Final Answer:

Thus 1 and 4 is the correct answer.