Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer and explanation
We are asked to calculate the partial pressure of each gas given the mass of the gasses
We can do this as follows
For H2
Mols = 3.93g/2.016 g/mol
= 1.95 mols
For NO
Mols = 38.4 g/ 30.01 g/mol
= 8.31 mols
the total number of mols then becomes:
8.31 + 1.95 =
10.26
and the mol fraction of each gas is determined by dividing the number of mols of that gas by the total number of mols
for H2 = 1.95/10.26
= 0.190
for NO = 8.31/10.26
= 0.809
now that we have the mols we can determine the pressures exerted by each gas by multiplying the total pressure by the mol fraction of each gas
for H2 the partial pressure is:
P(H2) = 3.01 atm x 0.190
= 0.572 atm
for NO the partial pressure is:
P(NO) = 3.01 atm x 0.809
= 2.44 atm
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
