Welcome to Westonci.ca, the place where your questions are answered by a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The vertical distance covered by freely falling feather is,
[tex]h=ut+\frac{1}{2}at^2[/tex]Since the feather is falling freely then the initial speed of feather is zero.
Plug in the known values,
[tex]\begin{gathered} 6.87\text{ m=(0 m/s)t+}\frac{1}{2}a(1.32s)^2 \\ a=\frac{2(6.87\text{ m)}}{(1.32s)^2} \\ \approx\text{7}.89m/s^2 \end{gathered}[/tex]Therefore, the free fall acceleration of the feather is 7.89 m/s2.
The speed of the feather at the bottom of the crater is,
[tex]v=u+at[/tex]Substitute the known values,
[tex]\begin{gathered} v=0m/s+(7.89m/s^2)(1.32\text{ s)} \\ \approx10.4\text{ m/s} \end{gathered}[/tex]Therefore, the speed of feather with which it strikes on the bottom of the crater is 10.4 m/s.
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.