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Sagot :
Hllo!
We have a cube with 6 different sides: 1, 2, 3, 4, 5, 6.
The exercise asks the probability of otaining 1 or 4.
First, let's think about the probability of obtaining the number 1.
Well, there's 1 option in 6 possible. So, we can write it as 1/6.
To obtain the number 4, we'll follow the same line of reasoning.
Now, remembr: we have the word "OR". It means tahat we have to sum up the obtained results.
Knowing it, let's calculate:
[tex]\begin{gathered} 1\text{ or 4} \\ \frac{1}{6}+\frac{1}{6}=\frac{1+1}{6}=\frac{2}{6} \end{gathered}[/tex]Now, let's simplify it by dividing the numerator and denominator by 2:
[tex]\frac{2\div2}{6\div2}=\frac{1}{3}[/tex]Answer:
1/3.
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