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I'm having trouble learning about this could you answer the question and show the steps of how you got it

Im Having Trouble Learning About This Could You Answer The Question And Show The Steps Of How You Got It class=

Sagot :

Step 1:

The area of the figure = Area of the trapezium + Area of a rectangle

Step 2:

The rectangle has dimensions of 7.8m by 6m

Find the area of rectangle A

[tex]\begin{gathered} \text{Area of the rectangle = Length }\times\text{ Breadth} \\ =\text{ 6 }\times\text{ 7.8} \\ =46.8m^2 \end{gathered}[/tex]

Step 3:

Area of trapezium

[tex]\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(\text{ sum of the length of parallel sides ) }\times\text{ height} \\ \text{Area of trapezium = }\frac{1}{2}(\text{ a+b ) }\times\text{ height} \\ a\text{ = 10m , b = 12m , height = 5m} \end{gathered}[/tex]

Next

Find the area of the trapezium B

[tex]\begin{gathered} \text{Area of trapezium = }\frac{1}{2}(\text{ a+b ) }\times\text{ height} \\ \text{Area of trapezium = }\frac{1}{2}(\text{ 12+10) }\times\text{ 5} \\ \text{Area of trapezium = }\frac{1}{2}(\text{22 ) }\times\text{5} \\ \text{Area of trapezium = }\frac{110}{2} \\ \text{Area of trapezium = }55m^2 \end{gathered}[/tex]

Total area = 46.8 + 55

[tex]\begin{gathered} \text{Total area = 46.8 + 55} \\ \text{Total area = 101.8 m}^2 \end{gathered}[/tex]

Final answer

[tex]\begin{gathered} \text{Area of rectangle = 46.8 m}^2 \\ \text{Area of trapezium = 55 m}^2 \\ Totalarea=101.8m^2 \end{gathered}[/tex]

View image KalevQ439967