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1. Two football players with mass 90 kg and 105 kg run directly toward each other withspeeds 5 m/s and 3 m/s respectively, if they grab each other as they collide, what is thecombined speed of the players just after the collision?

Sagot :

Given:

The mass of the first football player is m1 = 90 kg

The mass of the second football player is m2 = 105 kg

The initial speed of first football player is v_1i = 5 m/s

The initial speed of second football player is v_2i = 3 m/s

To find the speed of the combined mass after the collision.

Explanation:

According to the conservation of momentum,

[tex]\begin{gathered} m1v_{1i}+m2v_{2i}=(m1+m2)v_f \\ v_f=\frac{m1v_{1i}+m2v_{2i}}{(m1+m2)} \end{gathered}[/tex]

On substituting the values, the speed of the combined mass after the collision will be

[tex]\begin{gathered} v_f=\frac{(90\times5)+(105\times3)}{90+105} \\ =3.92\text{ m/s} \end{gathered}[/tex]

Final Answer: The speed of the combined mass after the collision is 3.92 m/s

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