Answered

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What is the magnitude of the force a 1.5 x 10^-7 C charge exerts on a 7.2 x 10 ^-5 C charge located 2.8 m away?

Sagot :

Given:

[tex]\begin{gathered} Q_1=1.5\times10^{-7}\text{ C} \\ Q_2=7.2\times10^{-5}\text{ C} \\ r=2.8\text{ m} \end{gathered}[/tex]

The electrostatic force is given as,

[tex]F=\frac{KQ_1Q_2}{r^2}[/tex]

Here, K is the electrostatic force constant.

Putting all values,

[tex]\begin{gathered} F=\frac{(9\times10^9\times1.5\times10^{-7}\times7.2\times10^{-5})^{}}{(2.8)^2} \\ =0.0124\text{ N} \end{gathered}[/tex]

Therefore, the magnitude of the force between the charges is 0.0124 N.

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