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Sagot :
Solution:
Given:
[tex]\begin{gathered} \text{slope}=4 \\ y-\text{intercept}=(0,-9) \end{gathered}[/tex]The equation of the line in slope-intercept form is given by;
[tex]\begin{gathered} y=mx+b \\ \\ \text{where m is the slope, m = 4} \\ b\text{ is the y-intercept, b = -9} \end{gathered}[/tex]Substituting these values into the equation of the line,
[tex]\begin{gathered} y=mx+b \\ y=4x+(-9) \\ y=4x-9 \end{gathered}[/tex]Therefore, the equation of the line in slope-intercept form is;
[tex]y=4x-9[/tex]
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