The area of a kite when both diagonals are given is
[tex]\text{Area}=\frac{diagona1\times diagonal2}{2}[/tex]
In our case, diagonal1=38 units and diagonal2=19. By substituting these values, we get
[tex]\text{Area}=\frac{38\times19}{2}[/tex]
which gives
[tex]\begin{gathered} A=\frac{722}{2} \\ A=361 \end{gathered}[/tex]
then, the ares is 361 units^2
