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Find the equation of the axis of symmetry for this function. f(x) = 5x2 - 6x + 12

Sagot :

For the function given as;

[tex]f(x)=5x^2-6x+12[/tex]

The axis of symmetry is the straight line that divides the parabola into 2 equal halves.

[tex]\begin{gathered} The\text{ x vertex is given as;} \\ x_{\text{vertex}}=-\frac{b}{2a} \\ In\text{ the equation,} \\ 5x^2-6x+12 \\ a=5,b=-6,c=12 \\ x_{\text{vertex}}=-\frac{-6}{2(5)} \\ x_{\text{vertex}}=\frac{6}{10} \\ x_{\text{vertex}}=\frac{3}{5}\text{ (thats }\frac{6}{10}\text{ in its simplest form)} \end{gathered}[/tex]