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Sagot :
Answer:
[tex]\boxed{y=-2x-10}[/tex]Explanation:
Step 1. The two points we have are:
[tex]\begin{gathered} (0,-10) \\ \text{and} \\ (-5,0) \end{gathered}[/tex]We will label these points as (x1,y1) and (x2,y2):
[tex]\begin{gathered} x_1=0 \\ y_1=-10 \\ x_1=-5 \\ y_1=0 \end{gathered}[/tex]Step 2. The second step is to find the slope ''m'' of the line, which is defined as follows:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Substituting the known values from step 1:
[tex]m=\frac{0-(-10)}{-5-0}[/tex]Solving the operations:
[tex]\begin{gathered} m=\frac{10}{-5} \\ \downarrow \\ m=-2 \end{gathered}[/tex]Step 3. Next, we need to find the y-intercept of the line.
The y-intercept is the value of y when the value of x is 0. In this case, we are already given this information in the first point:
(0, -10)
This indicates that the y-value is -10 when the x-value is 0.
The y-intercept is -10, this will be labeled as ''b'':
[tex]b=-10[/tex]Step 4. Use the values for ''m'' and ''b'' in the general slope-intercept equation:
[tex]y=mx+b[/tex]Substituting m and b:
[tex]\begin{gathered} \\ \boxed{y=-2x-10} \end{gathered}[/tex]Answer:
[tex]\boxed{y=-2x-10}[/tex]
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