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Hello If anyone is available.. I really need help on this. Question: 82 people were surveyed as to how many TVs they had in their homes.To one decimal place, what's the mean number of TVs owned by these households?

Hello If Anyone Is Available I Really Need Help On This Question 82 People Were Surveyed As To How Many TVs They Had In Their HomesTo One Decimal Place Whats Th class=

Sagot :

Using weighted mean, the mean is determined by

[tex]\begin{gathered} \overline{x}=\frac{\sum w_ix_i}{w_i} \\ \text{where} \\ x_i\text{ are the data set} \\ w_i\text{ is the weight, or the frequency} \end{gathered}[/tex][tex]\begin{gathered} \overline{x}=\frac{\sum w_ix_i}{w_i} \\ \overline{x}=\frac{1\cdot0+1\cdot10+2\cdot24+3\cdot21+4\cdot16+5\cdot9+6\cdot1}{1+10+24+21+16+9+1} \\ \overline{x}=\frac{0+10+48+63+64+45+6}{82} \\ \overline{x}=\frac{236}{82} \\ \overline{x}=2.87804878 \end{gathered}[/tex]

Rounding off to one decimal place, the mean number of TVs owned is 2.9.

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