Answered

Westonci.ca is the premier destination for reliable answers to your questions, provided by a community of experts. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

How much work must be done to stop a 1175 kg car traveling at 125 km/h?

Sagot :

According to Work energy theorem,

[tex]W=\frac{1}{2}mv^2-\frac{1}{2}mu^{2^{}^{}}^{}[/tex]

Finally, the car comes at rest therefore,

[tex]v=0\text{ m/s}[/tex]

Substitute the given value in the equation of work-energy theorem,

[tex]\begin{gathered} W=\frac{1}{2}(1175kg)(0m/s)^2(\frac{1\text{ J}}{1kgm^2s^{-2}})-\frac{1}{2}(1175\text{ kg)(}125km/h)^2(\frac{1000\text{ m}}{1\text{ km}})^2(\frac{1\text{ h}}{60\text{ min}})^2(\frac{1\text{ min}}{60\text{ s}})^2(\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ =0\text{ J-}708309\text{ J} \\ =-708309\text{ J} \end{gathered}[/tex]

Thus, the magnitude of work done to stop the car is 708309 J.

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.