Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
According to Work energy theorem,
[tex]W=\frac{1}{2}mv^2-\frac{1}{2}mu^{2^{}^{}}^{}[/tex]Finally, the car comes at rest therefore,
[tex]v=0\text{ m/s}[/tex]Substitute the given value in the equation of work-energy theorem,
[tex]\begin{gathered} W=\frac{1}{2}(1175kg)(0m/s)^2(\frac{1\text{ J}}{1kgm^2s^{-2}})-\frac{1}{2}(1175\text{ kg)(}125km/h)^2(\frac{1000\text{ m}}{1\text{ km}})^2(\frac{1\text{ h}}{60\text{ min}})^2(\frac{1\text{ min}}{60\text{ s}})^2(\frac{1\text{ J}}{1kgm^2s^{-2}}) \\ =0\text{ J-}708309\text{ J} \\ =-708309\text{ J} \end{gathered}[/tex]Thus, the magnitude of work done to stop the car is 708309 J.
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
