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Sagot :
In order to solve this question, we need to use proportions.
The dose of the dextrose bolus should be 0.5g for each gram of the dog's weight. Since the dog weighs 2 kg, we have the following proportions:
g of dextrose dog's weight in kg
0.5 1
x 2
So, the number of grams the dextrose bolus should have is x, which can be found by cross multiplying the above proportions:
x * 1 = 0.5 * 2
x = 1
Therefore, "Tiny" will receive 1 gram of dextrose.
Now, 1 gram is equivalent to 1000 mg.
Thus, "Tiny" will receive 1000 mg of dextrose.
Also, we are informed that the dextrose is a 50% solution, i.e., there is 500 mg of dextrose in 1 ml (milliliter). So, we have the following proportions:
mg of dextrose volume in ml
500 1
1000 y
So, cross multiplying, we obtain:
500 * y = 1000 * 1
y = 1000/500
y = 2
Therefore, "Tiny" will receive 2 ml of dextrose.
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