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Writing compound inequality with intergers for:c-6<=0 ; c-1>=8a. c<=-6 or c>=7b. c<=6 or c>=7c. c<=-6 or c>=9d. c<=6 or c>=9

Sagot :

We have two inequalities, and we need to solve for c:

First, add 6 to both sides of the inequality:

[tex]c-6\leq0\Rightarrow c-6+6\leq0+6\Rightarrow c\leq6_{}[/tex]

And

Second, add 1 to both sides of the inequality:

[tex]c-1\ge8\Rightarrow c-1+1\ge8+1\Rightarrow c\ge9[/tex]

Then, the answer as compound inequality with integers is:

[tex]\lbrace c\leq6,c\ge9\rbrace[/tex]

The answer is the previous expression {c <=6 or c>=9} (Option d).

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