Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
[tex]y=\frac{7}{8}x+\frac{57}{8}[/tex]
Explanation
Step 1
find the slope of the given line
[tex]y=\frac{7}{8}x+8[/tex]this equation is in the form, slope -intercept
[tex]y=mx+b[/tex]where m is the slope , so
[tex]\begin{gathered} y=\frac{7}{8}x+8\Rightarrow y=\text{ mx+b} \\ hence \\ m=slope=\frac{7}{8} \end{gathered}[/tex]Step 2
2 lines are parallel if the slope is the same,so we are looking for a line with slope 7/8 and the point c(1,8) is part of the line
use
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{where P1(x}_1,y_1)\text{ is a known point of the line} \end{gathered}[/tex]then
Let
P1=C=(1,8)
slope=7/8
now, replace
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-8=\frac{7}{8}(x-1) \\ y-8=\frac{7}{8}x-\frac{7}{8} \\ \text{add 8 in both sides} \\ y-8+8=\frac{7}{8}x-\frac{7}{8}+8 \\ y=\frac{7}{8}x+\frac{57}{8} \end{gathered}[/tex]I hope this helps you
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
