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Sagot :
Given:
The point charge has a magnitude
[tex]\begin{gathered} q=\text{ -4.8}\times10^{-19}\text{ C} \\ |q|=4.8\text{ }\times10^{-19\text{ }}C \end{gathered}[/tex]The distance is
[tex]r=\text{ 4}\times10^{-3}\text{ m}[/tex]To find the strength of the electric field.
Explanation:
The strength of the electric field can be calculated by the formula
[tex]E=\frac{k|q|}{r^2}[/tex]Here, the constant is
[tex]k=9\times10^9\text{ Nm}^2\text{ /C}^2[/tex]On substituting the values, the strength of the electric field will be
[tex]\begin{gathered} E=\frac{9\times10^9\times4.8\times10^{-19}}{(4\times10^{-3})^2} \\ =\text{ 2.7}\times10^{-4}\text{ N/C} \end{gathered}[/tex]
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