Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.
Sagot :
Let 'x' represent the length of the middle piece
We were told that the large piece is 5inches longer than the middle piece,
Mathematically, it means
[tex]x+5[/tex]Also, we were told that the shortest piece is 8inches shorter than the middle piece.
Mathematically, it means
[tex]x-8[/tex]Therefore, the sum of all three lengths must be 48inches.
Hence,
[tex]x+5+x+x-8=48[/tex]Solving for x
[tex]\begin{gathered} x+x+x+5-8=48 \\ 3x-3=48 \\ 3x=48+3 \\ 3x=51 \end{gathered}[/tex]Divide both sides by 3
[tex]\begin{gathered} \frac{3x}{3}=\frac{51}{3} \\ x=17 \\ \therefore The\text{ length of the middle piece=17inches.} \end{gathered}[/tex]Therefore,
The length of the large piece is,
[tex]\begin{gathered} x+5=17+5=22 \\ \therefore The\text{ length of the large piece is 22inches.} \end{gathered}[/tex]The length of the shortest piece is,
[tex]\begin{gathered} x-8=17-8=9 \\ \therefore The\text{ length of the shortest piece is 9inches.} \end{gathered}[/tex]Hence, the lengths of the three-piece are 9inches, 17inches, and 22inches.
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.