Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Let 'x' represent the length of the middle piece
We were told that the large piece is 5inches longer than the middle piece,
Mathematically, it means
[tex]x+5[/tex]Also, we were told that the shortest piece is 8inches shorter than the middle piece.
Mathematically, it means
[tex]x-8[/tex]Therefore, the sum of all three lengths must be 48inches.
Hence,
[tex]x+5+x+x-8=48[/tex]Solving for x
[tex]\begin{gathered} x+x+x+5-8=48 \\ 3x-3=48 \\ 3x=48+3 \\ 3x=51 \end{gathered}[/tex]Divide both sides by 3
[tex]\begin{gathered} \frac{3x}{3}=\frac{51}{3} \\ x=17 \\ \therefore The\text{ length of the middle piece=17inches.} \end{gathered}[/tex]Therefore,
The length of the large piece is,
[tex]\begin{gathered} x+5=17+5=22 \\ \therefore The\text{ length of the large piece is 22inches.} \end{gathered}[/tex]The length of the shortest piece is,
[tex]\begin{gathered} x-8=17-8=9 \\ \therefore The\text{ length of the shortest piece is 9inches.} \end{gathered}[/tex]Hence, the lengths of the three-piece are 9inches, 17inches, and 22inches.
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.
