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Use the frequency distribution to complete parts (a)through (e).Class7-15a) Determine the total number of observations.16-24b) Determine the width of each class.25-33c) Determine the midpoint of the second class.34-42d) Determine the modal class (or classes).e) Determine the class limits of the next class if anadditional class were to be added.43-5152-607a) The total number of observations isb) The width of each class isc) The midpoint of the second class is(Type an integer or a decimal.)d) The modal class(es) is/are(Use a hyphen to separate the limits of a class. Use a comma to separate answers. Type the classes in order from smallest to largest.)Time Remaining: 08Frequency33156LT0#

Use The Frequency Distribution To Complete Parts Athrough EClass715a Determine The Total Number Of Observations1624b Determine The Width Of Each Class2533c Dete class=

Sagot :

The Solution:

Given:

We are required to answer the following questions:

(a) Determine the total number of observations.

[tex]\begin{gathered} \text{ Total number of observations is the sum of all the frequencies.} \\ \text{ T }=3+1+5+6+1+7=23\text{ observations} \end{gathered}[/tex]

(b) The width of each class.

[tex]\begin{gathered} The\text{ width of each class is the size of each class.} \\ Class\text{ Width}=15-7=24-16=8 \end{gathered}[/tex]

(c) The midpoint of the second class is:

[tex]\begin{gathered} The\text{ midpoint of class }16-24. \\ =\frac{24-16}{2}=\frac{8}{2}=4 \\ \\ So,\text{ }16+4=20 \\ \text{ Thus, the midpoint of the second class is 20.} \end{gathered}[/tex]

(d) The modal class is the class with the highest frequency.

So, the modal class is 52 - 60.

(e) The additional class added is 61 - 68.

The class limit of the additional class is:

[tex]\begin{gathered} 60.5-68.5 \\ the\text{ lower limit is 60.5} \\ the\text{ upper limit is 68.5} \end{gathered}[/tex]

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