Answered

Westonci.ca connects you with experts who provide insightful answers to your questions. Join us today and start learning! Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

You have 134,720 grams of a radioactive kind of actinium. How much will be left after 50 days if its half-life is 10 days?

Sagot :

Given:

The initial quantity of the actinium that will decay is 134720 grams.

Time, t=50 days

The half-life of the decaying quantity is 10 days.

To find the quantity that still remains after time t:

The half-life formula is given by,

[tex]N(t)=N_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}[/tex]

On substitution we get,

[tex]\begin{gathered} N(50)=134720(\frac{1}{2})^{\frac{50}{10}} \\ =134720\times(\frac{1}{2})^5 \\ =134720\times0.03125 \\ =4210\text{ grams} \end{gathered}[/tex]

Hence, the quantity that still remains after time 50 days is 4210 grams.

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Stay curious and keep coming back to Westonci.ca for answers to all your burning questions.