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Find a point on the line and the slope of the line(y+5)=(x+1)

Find A Point On The Line And The Slope Of The Liney5x1 class=

Sagot :

Solution:

Consider the following equation for a line:

[tex]y+5\text{ = x+1}[/tex]

to find the slope of this line, we must transform this equation to the form slope-intercept:

y = mx+b

where m is the slope of the line and b is the y-intercept of the same line.

First, solve the given equation for the variable y:

[tex]\text{y = x+1-5}[/tex]

this is equivalent to:

[tex]y=x-4[/tex]

then, the slope of this line is:

[tex]1[/tex]

now, to find any point on the line, take x=0, and replace it into the equation of the given line:

[tex]y=f(0)=0-4=-4[/tex]

thus, one point on the line would be:

[tex](0,-4)[/tex]

so that, the correct answers are:

SLOPE:

[tex]1[/tex]

POINT ON THE LINE:

[tex](0,-4)[/tex]

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