Answered

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quation of a line passing through (5, -6) parallel to: E 12 (d) 7x - 12y = 5 (f) 2y = 5

Sagot :

Input data

A = (5, -6)

[tex]7x-12y=5[/tex]

Procedure

First we must determine the slope of the straight line to make it parallel

[tex]y=\frac{7}{12}x-\frac{5}{12}[/tex]

The slope of the straight line would be m = 7/12

[tex]\begin{gathered} b=y-mx \\ b=-6-\frac{7}{12}\cdot5 \\ b=-6-\frac{35}{12} \\ b=-\frac{72}{12}-\frac{35}{12} \\ b=-\frac{107}{12} \end{gathered}[/tex]

The equation of the line that passes through the point (5,-6) with a slope of 7/12 is

[tex]y=\frac{7}{12}x-\frac{107}{12}[/tex]

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