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Find two complementary angles such that the measure of the larger angle is 18° more than the measure of the smaller angle.

Sagot :

Complementary angles add up to 90degrees.

Let's make the larger angle x degrees, so the smaller angle would be x - 18 degrees.

Thus, we have;

[tex]\begin{gathered} x+x-18=90 \\ 2x-18=90 \\ 2x=108 \\ x=\frac{108}{2}=54^o \\ \text{and } \\ x-18=36^o \end{gathered}[/tex]

Therefore, the two angles are 54 and 36 degrees.