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Find the area of a regular octagon witha side length of 5 cm. Round to thenearest tenth.5 cm[? ] cm2

Find The Area Of A Regular Octagon Witha Side Length Of 5 Cm Round To Thenearest Tenth5 Cm Cm2 class=

Sagot :

The regular octagon can be divided into 8 congruent isosceles triangle

so

The area of the regular octagon is the same that the area of 8 congruent isosceles triangles

so

See one isosceles triangle in the figure below

Find out the height of the triangle

tan(67.5)=h/2.5

h=2.5*tan(67.5)

the area of the regular octagon is equal to

A=8*(1/2)*[5*2.5*tan(67.5)]

A=120.7 cm2

View image FathimaP285651
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