Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Given,
Three masses
m₁=2 kg
m₂=3 kg
m₃=1 kg
The coordinate of mass 1 is (x₁,y₁)=(0,0)
The coordinate of mass 2 is (x₂,y₂)=(-1,0)
The coordinate of mass 3 is (x₃,y₃)=(1,1)
The x-coordinate of the center of mass is given by,
[tex]x=\frac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3}[/tex]On substituting the known values,
[tex]\begin{gathered} x=\frac{2\times0+3\times-1+1\times1}{2+3+1} \\ =-\frac{1}{3} \end{gathered}[/tex]And the y-coordinate of the center of mass is given by,
[tex]y=\frac{m_1y_1+m_2y_2+m_3y_3}{m_1+m_2+m_3}[/tex]On substituting the known values,
[tex]\begin{gathered} y=\frac{2\times0+3\times0+1\times1}{2+3+1} \\ =\frac{1}{6} \end{gathered}[/tex]Thus the center of mass is at (-1/3, 1/6)
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
