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I'm confused apparently I have to use this graph to determine the instantaneous rate of change x= – 1 and I'm not exactly sure how to do that. I also have to determine the average rate of change on the interval -1 ≤ X ≤ 2

Im Confused Apparently I Have To Use This Graph To Determine The Instantaneous Rate Of Change X 1 And Im Not Exactly Sure How To Do That I Also Have To Determin class=

Sagot :

Answer

• The instantaneous rate of change at x= – 1 is 0 (zero).

• The average rate of change on the interval -1 ≤ x ≤ 2 is –4/3.

Explanation

The instantaneous rate of change is the derivative at the point given. In our case, when x = –1, it is a maximum point and the tangent to this line is a constant y = –3 (tangent line represented by the blue line in the figure given). Thus, the derivative is 0, resulting in an instantaneous rate of change of 0:

Contrarily, the average rate of change on the interval –1 ≤ X ≤ 2 is the slope of the tangent line between points x = –1 and x = –2 (represented by the red line in the figure given), then, the slope can be calculated using the following formula:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Then, to use this formula we have to find the coordinates of these points:

Thus, the coordinates are (–1, 3) and (2, –1), by replacing these values we get:

[tex]m=\frac{-1-3}{2-(-1)}[/tex][tex]m=\frac{-4}{2+1}[/tex][tex]m=-\frac{4}{3}[/tex]

View image TaylinnU502506
View image TaylinnU502506