Write out the general formula for finding the volume of a cone and a cylinder
[tex]\begin{gathered} V_{\text{cone}}=\frac{1}{3}\pi r^2h \\ V_{\text{cylinder}}=\pi r^2h \end{gathered}[/tex]Write out the given parameter in the question
[tex]\begin{gathered} r_{\text{cone}}=1\text{ofeet} \\ h_{\text{cone}}=10\text{feet} \\ r_{\text{cylinder}}=10\text{feet} \\ h_{\text{cylinder}}=30\text{feet} \end{gathered}[/tex]Substitute the given into the formula
[tex]V_{\text{cone}}=\frac{1}{3}\pi r^2h=\frac{1}{3}\times3.14\times10^2\times10=1046.67ft^3[/tex][tex]V_{\text{cylinder}}=\pi r^2h=3.14\times10^2\times30=9420ft^3[/tex]The volume of the silo is the addition of the volume of the cone and the volume of the cylinder
[tex]V_{\text{silo}}=1046.67ft^3+9420ft^3=10466.67ft^3(\text{nearest hundredth)}[/tex]Hence, the volume of the silo is 10466.67ft³