Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get immediate and reliable solutions to your questions from a community of experienced experts on our Q&A platform. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Determine the factor of change for the electric force if the distance is changed by a factor of 3 and the charges of one of particles is changed by a factor of 4

Sagot :

Take into account that the electric force between two charges q1 and q2, separated by a distance r, is given by:

[tex]F=K\frac{q_1q_2}{r^2}[/tex]

where K is the Coulomb's constant.

If r is changed to 3r and q1 is changed to 4q1, the new force F' is given by:

[tex]\begin{gathered} F^{\prime}=K\frac{(4q_1)(q_2)}{(3r)^2}=\frac{4}{9}K\frac{q_1q_2}{r^2} \\ F^{\prime}=\frac{4}{9}F \end{gathered}[/tex]

Hence, the factor of change of the electric force is 4/9