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Sagot :
[tex]y=3.1x+1.8[/tex]
Explanation
Step 1
find the slope of the line
[tex]\begin{gathered} \text{slope}=\frac{change\text{ in y}}{\text{change in x}}=\frac{y_2-y_1}{x_2-x_1} \\ where \\ P1(x_1,y_1) \\ P2(x_2,y_2) \end{gathered}[/tex]where P1 and P2 are 2 coordinates of the line
Let
P1=(12,39)
P2=(42,132)
replace,
[tex]\begin{gathered} \text{slope}=\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{132-39}{42-12} \\ \text{slope}=\frac{93}{30} \\ \text{slope}=3.1 \end{gathered}[/tex]Step 2
find the equation of the line,use
[tex]y-y_1=m(x-x_1)[/tex]replace
[tex]\begin{gathered} y-39=3.1(x-12) \\ y-39=3.1x-37.2 \\ \text{add 39 in both sides} \\ y-39+39=3.1x-37.2+39 \\ y=3.1x+1.8 \end{gathered}[/tex]I hope this helps you
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