Answered

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Which equation represents a line that is perpendicular to y = 5x + 2 and goes throughthe point (-10, 3)?

Sagot :

The slope of the given line is 5 because that's the coefficient of x.

Then, we use the following formula to find the perpendicular slope.

[tex]\begin{gathered} m=-\frac{1}{m_1} \\ m=-\frac{1}{5} \end{gathered}[/tex]

Then, we use the point-slope formula.

[tex]\begin{gathered} y-y_1=m(x-x_1)_{} \\ y-3=-\frac{1}{5}(x-(-10))_{} \\ y-3=-\frac{1}{5}(x+10) \\ y=-\frac{1}{5}x-2+3 \\ y=-\frac{1}{5}x+1 \end{gathered}[/tex]

Therefore, the equation is y = -1/5x + 1.

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