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Sagot :
Assuming the number of moles give is of CO₂, since we know that 1 mol is equivalent to 22.4 L in this case, we can use rule of three to answer this:
V ---- n
x ---- 3.75 mol
22.4 L ---- 1 mol
So, we have the follwing relation:
[tex]\begin{gathered} \frac{x}{22.4L}=\frac{3.75}{1} \\ x=3.75\cdot22.4\cdot L \\ x=84L \end{gathered}[/tex]So, we need a volume of 84 L.
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