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A person wearing the shoes has a mass of 59 kg. Estimate the pressure exerted on a floor by one wide heel of area 16 cm^2.

Sagot :

We know that

• The mass is 59 kg.

,

• The area is 16 cm^2.

The formula of pressure is

[tex]P=\frac{F}{A}[/tex]

Where F refers to the weight of the person, W = mg. The acceleration of gravity is 9.81 m/s^2.

[tex]P=\frac{mg}{A}=\frac{59\operatorname{kg}\cdot9.81(\frac{m}{s^2})}{0.0016m^2}[/tex]

Note that 16 cm^2 = 0.0016 m^2.

[tex]P\approx361,743.75Pa[/tex]

Therefore, the pressure exerted on the floor is 361,743.75 Pa.