Nevaeh left her house at time zero and drove for 2 minutes to the store at a speed of 1 block per minute. Then she stopped and went into the store for 4 minutes. From there, she drove in the same direction at a speed of 2 blocks per minute until she got to the bank, which is 8 blocks away from the store. She stopped at the bank for 2 minutes. Then she drove home at a speed of 5 blocks every 3 minutes. Make a graph of showing the number of blocks away from home that Nevaeh is x minutes after she leaves her house, until she gets back home. Can you do do it on this graph?

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04-11-2022
Mathematics

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Nevaeh left her house at time zero and drove for 2 minutes to the store at a speed of 1 block per minute. Then she stopped and went into the store for 4 minutes. From there, she drove in the same direction at a speed of 2 blocks per minute until she got to the bank, which is 8 blocks away from the store. She stopped at the bank for 2 minutes. Then she drove home at a speed of 5 blocks every 3 minutes. Make a graph of showing the number of blocks away from home that Nevaeh is x minutes after she leaves her house, until she gets back home. Can you do do it on this graph?

Sagot :

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KawtharI790264 KawtharI790264 · Answer 1 · 2022-11-04T07:53:23-04:00

ksWe need to first calculate our junctions on the graph.

Firstly, she drives for 2 minutes to the store at 1 block per minute giving her total distance driven as:

[tex]2\min \times\frac{1block}{\min ute}=2blocks[/tex]

Then she stays in the same place for 4 minutes, giving us a zero gradient.

At this point, she has spent 6 minutes and covered 2 blocks

She also drives to the bank, 8 blocks from the store at 2 blocks per minute giving time spent as:

[tex]8b\text{locks }\div\text{ 2 blocks per minute = 4 minutes}[/tex]

At this point, she has driven 10 blocks and spent 10 minutes.

She spends 2 minutes thus, we have no gradient. We now have spent 12 minutes at that point.

Lastly, she drives back home 10 blocks away at the speed of 5 blocks per 3 minutes.

Therefore, time spent on the journey home:

[tex]\frac{10\min utes}{\frac{5blocks}{3\min s}}=\frac{10}{5}\times3=6\min utes[/tex]

So, at this point, we are at 18 minutes and 0 distance.

The graph:

Sagot :

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