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Find the area. Round to the nearest hundredth when necessary. 16 in Area in? 2

Sagot :

We have the next figure

Because we have an irregular figure we divide the figure into a rectangle and in a triangle

For the area of the rectangle

[tex]A=l\times w[/tex]

l=length

w= width

In our case

l=19

w=16

we substitute the values

[tex]A=19\times16=304in^2[/tex]

for the area of the triangle

[tex]A=\frac{b\times h}{2}[/tex]

b= base

h=height

in our case

b=16in

h=30-19=11in

we substitute the values

[tex]\begin{gathered} A=\frac{16\times11}{2} \\ A=88in^2 \end{gathered}[/tex]

Then we sum the areas of the figures and we obtain the total are

[tex]\begin{gathered} A=304+88 \\ A=392in^2 \end{gathered}[/tex]

View image TaureanX197658
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