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Sagot :
Triangle of sides ratio 1 : 1 : 2 is an isosceles triangle, with a diagram given above to illustrate it.
With the ratio of the sides given,
Largest side of the triangle is 4 units, let the length of the shortest side be x
Using scale ratio to determine the shortest side,
[tex]\begin{gathered} \text{Scale ratio of the sides =}\frac{shortest\text{ side}}{largest\text{ side}}=\frac{1}{2} \\ \text{Actual length ratio = }\frac{shorstest\text{ side}}{largest\text{ side}}=\frac{x}{4} \\ \text{Equating both ratios} \\ \frac{x}{4}=\frac{1}{2} \\ \text{Crossmultiply} \\ 2\times x=4\times1 \\ 2x=4 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{4}{2} \\ x=2 \end{gathered}[/tex]Hence, the length of the shortest side is 2 units.

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