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Find the equation of the line with slope m=5/3 that contains the point (-6,-12)

Find The Equation Of The Line With Slope M53 That Contains The Point 612 class=

Sagot :

Okay, here we have this:

Slope m=5/3

Pass through the point (-6,-12) and let (x,y) be other point of the line.

m=(x2 - x1)/(y2 - y1)

Replacing we obtain:

(-6 - x)/(-12 - y) = 5/3

Working we obtain:

3 (- 6 - x) = 5 (- 12 - y)

-18 - 3x = -60-5y

-18 - 3x +60+5y = 0

3x - 5y - 42 = 0 (Multiplying by -1 on both sides)

3x - 5y = 42 This is the equation of the line

Clearing y:

y=(42-3x)/-5

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