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Sagot :
Much net work that must be done on the particle to cause it to move to the right at 43 m/s, [tex]w_{net}[/tex] =22.87J
Work Done on a Body:
Total work done is the change in kinetic energy.
mathematically, Total work done is given by: [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex]- [tex]\frac{1}{2}[/tex]m[tex]u^{2}[/tex]
Where:
u = the initial velocity of the body and is given as 26m/s
v =the final velocity of the body and is given as ;43m/s
m =mass of the body m= 39g = 0.039kg
[tex]w_{net}[/tex] = net work
[tex]w_{net}[/tex] = Δke= [tex]\frac{1}{2}[/tex]m[tex]v^{2}[/tex]- [tex]\frac{1}{2}[/tex]m[tex]u^{2}[/tex]
Insert the given to the equation
where have,
[tex]w_{net}[/tex] = [tex]\frac{1}{2}[/tex] (0.039)([tex]43^{2}[/tex]) - [tex]\frac{1}{2}[/tex] (0.039)([tex]26^{2}[/tex])
[tex]w_{net}[/tex] = 36.05 - 13.18
[tex]w_{net}[/tex] = 22.87J
Therefore, the net work that must be done on the particle to cause it to move to the right at 43 m/s, =22.87J.
Learn more about workdone here: https://brainly.com/question/25923373
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