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Sagot :
The magnitude of the concentration that LiOH(aq) employs to neutralize the reaction is 0.125 M.
What is the concentration of LiOH(aq)?
[tex]M__{H_{2}SO_4 }[/tex] = M₁ = 0,050 M
[tex]V__{H_{2}SO_4 }[/tex] = V₁ = 20,0 ml
[tex]V__{LiOH }[/tex] = V₂ = 8,00 ml
Thus, solving for the final morality is:
M₁V₁ = M₂V₂
M₂ = [tex]\frac{M_1V_1}{V_{2}}[/tex]
So, plugging in the values we obtain:
M₂ = [tex]\frac{0,050x20,0}{8,00}[/tex]
M₂ = 1 : 8,00
M₂ = 0,125 M
Then the magnitude of the concentration that LiOH employs to neutralize the reaction is 0.125 M.
Learn more about calculating the concentration of the solution at https://brainly.com/question/19091247
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