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Sagot :
The time taken by the ball kicked with a velocity of 15 m/s at an angle of 60° to the horizontal to reach the highest point of its path is 2.66 s
t = 2 u sin θ / g
t = Total time of flight
u = Initial velocity
θ = Angle of projection
g = Acceleration due to gravity
u = 15 m / s
θ = 60°
g = 9.8 m / s²
t = 2 * 15 * sin 60° / 9.8
t = 26.1 / 9.8
t = 2.66 s
The time taken by a projectile to reach the highest point will be equal to the time taken by the projectile to reach the ground from there.
T = t / 2
T = 2.66 / 2
T = 1.33 s
Therefore, the time taken by the ball to reach the highest point of its path is 1.33 s
To know more about projectile motion
https://brainly.com/question/11049671
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