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Sagot :
The momentum at the end of the 1.5s of a hockey puck of mass 150.0 g is sliding due east with a speed of 10.0 m/s for northward and eastward component is 7.5 kg m / s and 1.5 kg m / s respectively.
For northward component,
Δp = F Δt
Δp = Change in momentum
F = Net force
Δt = Change in time
Δp = pf - pi
f = 5 N
Δt = 1.5 s
pi = 0 ( Since there is no momentum North )
pf = 5 * 1.5
pf = 7.5 kg m / s
For eastward component,
p = m v
m = Mass
v = Velocity
Since the force is acting perpendicular to velocity, there will be no change in velocity. So momentum remains constant for eastward component.
m = 150 g = 0.15 kg
v = 10 m / s
p = 0.15 * 10
p = 1.5 kg m / s
Therefore, the momentum of northward and eastward component is 7.5 kg m / s and 1.5 kg m / s respectively.
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