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solve this equation
5x+2=3x-20-1x

Sagot :

[tex]5x+2=3x-20-1x\\5x+2=2x-20\ \ \ \ |subtract\ 2\ from\ both\ sides\\5x=2x-22\ \ \ \ |subtract\ 2x\ from\ both\ sides\\3x=-22\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{x=-\frac{22}{3}}\Rightarrow\boxed{x=-7\frac{1}{3}}[/tex]
apologiabiology
5x+2=3x-20-1x
add like terms
5x+2=(3-1)x-20
5x+2=2x-20
subtract 2x from both sdies
5x-2x+2=2x-2x-20
3x+2=0-20
subtract 2 from both sides
3x+2-2=-20-2
3x=-22
divide both sides by 3
x=-22/3 or -7 and 1/3
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