Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

the radius of a right circular cone is increasing at a rate of 1.3 in/s while its height is decreasing at a rate of 2.1 in/s. at what rate is the volume of the cone changing when the radius is 122 in. and the height is 147 in.?

Sagot :

varshamittal029

We need to know about the rate of change to solve the problem. The rate of change of the volume of the cone is 16097.52 cubic in/s

The rate of change of a quantity is the rate at which it either increases or decreases. In this question we know that the radius is increasing at a rate of 1.3 in/s, height is decreasing at a rate of 2.1 in/s, we need to find the rate of change of volume given the radius is 122 in and the height is 147 in.

volume of a cone=[tex]\pi r^{2}[/tex]h/3

dV/dt=[tex]\pi[/tex]/3(2rh dr/dt+[tex]r^{2}[/tex] dh/dt)=[tex]\pi[/tex]/3(2x122x147x1.3 -122x122x2.1)=16097.52

Therefore the change in volume is 16097.52 cubic in/s.

Learn more about rate of change here:

https://brainly.com/question/20884505

#SPJ4

Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.