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2. assume you are taking two courses this semester (a and b). the probability that you will pass course a is 0.835, the probability that you will pass both courses is 0.276. the probability that you will pass at least one of the courses is 0.981.2(c). what is the probability that you will pass course b given that you pass course a?

Sagot :

The probability that you will pass course B is 0.422

No, the passing of the two courses independent events P(A) * P(B) = 0.35237.

It's not mutually exclusive events.

Given that,

Let's say you're enrolled in two classes each this semester, A and B.

The probability that you will pass the course a is 0.835, the probability that you will pass both courses is 0.276, the probability that you will pass at least one of the courses is 0.981

Now, we need to solve the following conditions;

(a) What is the probability that you will pass course B?

P(A) = 0.835

P( A ∩ B) = 0.276

P( A ∪ B) = 0.981

P(B) = P(A ∪ B) - P(A) + P(A ∩ B)

      = 0.981 - 0.835 + 0.276

      = 0.422

(b) Use statistical data to support your conclusion as to whether the passing of the two courses constitutes independent events.

No,

P(A ∩ B) != P(A) * P(B)

P(A) * P(B) = 0.422* 0.835  

                 = 0.35237

P( A ∩ B)  = 0.276

(c)Are the activities required to pass the courses exclusive,

P(A ∩ B) ! =0, it's not mutually exclusive events

Therefore, The probability that you will pass course B is 0.422

To learn more about probability click here:

brainly.com/question/14210034

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