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two crates, of mass 65 kg and 125 kg, are in contact and at rest on a horizontal surface. a 650 n force is exerted on the 65 kg crate. if the coefficient of kinetic friction is 0.18, calculate the (a) the acceleration of the system, and (b) the force that each crate exert on the other. (c) repeat with the crates reversed.

Sagot :

The apparatus accelerates at a speed of 1.65 m/s2. One crate presses down on another with a force of 426.75 N. The force applied by one crate to the other when the containers are flipped around is 221.91 N.

Acceleration in mechanics refers to the rate of change in a moving object's velocity with respect to time. A measure of acceleration in a vector (in that they have magnitude and direction). An object's acceleration with respect to a force depends on the direction of the net force acting on it.

Although it could seem challenging, velocity is just the act of travelling swiftly in a specific direction. The rate of change in an object's location relative to a frame of reference and time is referred to as its velocity.

As a result,

The initial containers weighed 65 kg.

Weight of the second crates is 125 kg.

650 N of force

Kinetic friction coefficient is equal to 0.18 a, or 650/(65+120) - 0.18*9.8 a, which equals 1.65 m/s2.

Each box presses on the others with a force of F= 125*1.65*0.18*125*9.8 F= 426.75N.

When the containers are turned around, the force each one applies to the other

F=125*1.65*0.18*125*9.8\s

F=221.91N

Learn more about acceleration here

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