Answered

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Calculate the heat capacity of 1,343 g of lead, given that 45 j is needed to raise the temperature by 29. 8 ∘c.

Sagot :

It is discovered that lead has a specific heat of 0.0011 J/C.

The heat capacity of a substance is a measurement of how much heat is needed to elevate body temperature by one degree Celsius.

Heat change is provided by,

Q = mcT

Where,

Did the temperature change?

The heat capacity of the is c.

The body's mass is m,

T stands for temperature change.

Lead weighs 1343 grams, and its temperature and heat change by 29.8 degrees Celsius and 45J, respectively.

Assigning values,

c = 45/(29.8x1343) (29.8x1343)

Per degree Celsius, c equals 0.0011 Joules.

the specific heat is 0.0011 J/C as a result.

Visit to learn more about specific heat :

brainly.com/question/21406849

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