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Sagot :
The percentage of carbon-14 that will remain in a sample after 1.99 x 10⁴ years is 9.01%.
Half-life is defined as the time it will took a substance to reduce to half of its initial amount. The half-life of a substance is determined with respect to the rate of the reaction. It can be calculated using the formula below.
N(t) = N₀(1/2)^(t/T)
where N(t) = amount of substance remaining after time t
N₀ = initial amount of substance
t = time = 1.99 x 10⁴ years
T = half-life = 5730 years
Plug in the given values to the equation.
N(t) = N₀(1/2)^(t/T)
N(t) = N₀(1/2)^(1.99 x 10⁴ years/5730 years)
N(t) = N₀(0.09006)
Hence, the percentage that will remain is 9.01%.
N(t) / N₀ = 0.09006
N(t) / N₀ = 9.01%
Learn more about half-life here: https://brainly.com/question/3788119
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