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suppose you sell sandwiches at a deli store. review of your sales transactions reveals that 73.5% of your customers will choose turkey breast sandwiches and the rest will choose some other sandwich. (round all answers to 4 decimal places) if five people are randomly selected, what is the probability that all will order a turkey breast sandwich? if five people are randomly selected, what is the probability that none will order a turkey breast sandwich? if five people are randomly selected, what is the probability that at least one customer will order a turkey breast sandwich?

Sagot :

Using the binomial distribution, the probabilities are given as follows:

  • All: 0.2145 = 21.45%.
  • None: 0.0013 = 0.13%.
  • At least one: 0.9987 = 99.87%.

What is the binomial distribution formula?

The probability mass function for the binomial distribution is presented as follows:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters of the distribution are given by:

  • n is the number of trials of the experiment.
  • p is the probability of a success on a single trial of the experiment.

In the context of this problem, the values of these parameters are:

n = 5, p = 0.735.

The probability of all people ordering the breast sandwich is:

P(X = 5) = 0.735^5 = 0.2145 = 21.45%.

The probability of no people ordering the breast sandwich is:

P(X = 0) = (1 - 0.735)^5 = 0.0013 = 0.13%.

The probability of at least one person ordering the breast sandwich is:

P(X >= 1) = 1 - 0.0013 = 0.9987 = 99.87%.

More can be learned about the binomial distribution at https://brainly.com/question/24756209

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