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Sagot :
Hardy-Weinberg equilibrium state of the population, the total frequency of an allele and its alternate allele in a population is p + q = 1. Therefore the frequency of the alternate allele q in the starting population is
q = (1 - 0.7) = 0.30.
An allele frequency is calculated by dividing the number of times the allele of interest is observed in a population by the total number of copies of all the alleles at that particular genetic point in the population.
For example if allele frequency is 0.5 it mean , a person has a 0.5 chance of passing on one of two alleles for a given gene. If the allele frequencies of p and q is equal 1 the two alleles when combined gives the frequency equal 100%.
To learn more about Hardy-Weinberg equilibrium , here
brainly.com/question/16823644
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