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Sagot :
Answer:
382.2 N
Explanation:
You want the normal force on an object weighing 437 N situated on an inclined plane 29° from the horizontal.
Force vector
The vector 437 N straight down can be decomposed to vectors parallel to the plane and perpendicular to the plane. That decomposition looks like ...
(perpendicular, parallel) = 437 N · (cos(29°), sin(29°)) ≈ (382.2, 211.9) N
The normal force on the object is about 382.2 N.

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