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A plane is flying to Minnesota with a velocity of 373.52 km/h, N. The plane encounters a crosswind with a velocity of 64.90 km/h, W. What is the magnitude of the resultant velocity of the plane?

Sagot :

sqdancefan

Answer:

  379.12 km/h N 9.86° W

Explanation:

You want to know the resultant velocity when a plane's velocity of 373.52 km/h N is modified by a crosswind at 64.90 km/h W.

Vector sum

In (N, E) coordinates, the sum of the velocities is ...

  (373.52, 0) +(0, -64.90) = (373.52, -64.90)

The magnitude of this vector is ...

  |v| = √(373.52² +64.90²) ≈ 379.12 . . . . km/h

The direction will be west of north by the angle ...

  θ = arctan(-64.90/373.52) ≈ -9.86° . . . . . . N = 0°, + = clockwise

The resultant velocity is 379.12 km/h N 9.86° W.

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